Question

find the compound interest of Rupees 6500 for 2 years at 9% pat annul .

Answer 1

Answer:

1222.65

Step-by-step explanation:

$\implies$ $A=P(1+{\Large\frac{r}{100}})^{n}$

$\implies$ $A=6500(1+{\Large\frac{9}{100}})^{2}$

$\implies$ $A=6500({\Large\frac{109}{100}})^{2}$

$\implies$ $A=6500×{\Large\frac{109}{100}}×\Large\frac{109}{100}$

$\implies$ $A=7,722.65$

$\implies$ $C.I=A-P$

$\implies$ $C.I=7722.65-6500$

$\implies$ $\boxed{CI=1222.65}$

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