Question

find the compound interest of the following principal is 10000 rate of per annum is 12% number of year 2

Answer 1

Your Answer is...
$amount = principal( {1 + rate \div 100})^{time} \\ = 10000( {1 + 12 \div 100})^{2} \\ = 10000 \times 112 \div 100 \times 112 \div 100 \\ = 12544 \\ \\ compound \: intrest \: = amount - principal \\ = 12544 - 10000 \\ = 2544$
Compound Intrest =2544

Hope it helps...