Question

Find the compound interest on 10,000, at 10% per annum for 3 years.​

Answer 1

Answer:

₹3310

Step-by-step explanation:

principal =10000

rate of interest =10%

time =3years

compound interest =amount-Principal

so Amount

=

$p {(1 + \frac{ r}{100} })^{3} \\ = 10000 {( \frac{1 00+ 10}{100} )}^{3} \\ 10000 \times \frac{110}{100} \times \frac{110}{100} \times \frac{110}{100} \\ = 110 \times 11 \times 11 = rs13310$

compound interest =₹13310-₹10000=₹3310

Answer 2

$\huge\text{Given}$

$\sf \red{Principle(p)= RS \: 10,000}$

$\sf \pink{Rate (R)= 10\%}$

$\small \text \red{Number of year n = 3 \: years}$

$\sf\pink{Comound \: Interest \: (C I) = ?}$

$\huge\text{Explanation}$

• We have to calculate firstly amount in order to find Comound Interest.

$\sf \blue{We \: know \: that}$

$\sf\huge \purple{A=P(1+ \frac{r}{100}) ^{n} }$

$\sf{ = > 10,000 = }(1 + \frac{10}{100} {)}^{3}$

$\sf{ = > 10,000 \times \frac{11}{10} \times \frac{11}{10} \times \frac{11}{10} }$

$\sf{ = > \frac{13,310,000}{1000} }$

$\sf \blue{ = > 13,310 \: RS}$

$\sf \green{We \: know \: that}$

$\sf\pink{Comound \: Interest \: (C I) =Amount-Principle }$

$\sf{ = > 13310 - 10000}$

$\large\boxed{ =>3310 RS}$