Question

find the compound interest on 1000 rupees for 2 years at 4% per annum​

Answer 1

Answer:

we know that

CI = P * { 1 +(R/100)}^T - P

so

CI = 1000 { 1+ (4/100)}^2 - 1000

CI = 1000 { 104/100}^2 - 1000

CI = 1081.60 - 1000

CI = 81.6 rupees

Answer 2

$\sf \: The~compound~interest~is~ Rs. 81.60$

~~Full solution is given in the attachment