Find the compound interest on ₹10000 at 8% per annum for 6 months compounded quarterly.
Answers
Answer:
Step-by-step explanation:
Given,
Principal, P = 10,000
Rate of interest compounded quarterly, R = 8 % = 8/4 = 2 %
Time = 6 months = 6/12 × 4 = 2 quarters.
To Find,
Compound Interest
Formula to be used,
Amount, A = P × (1 + R/100)^n
Solution,
Putting all the values, we get
⇒ Amount, A = P × (1 + R/100)^n
⇒ Amount, A = 10,000 × (1 + 2/100)^2
⇒ Amount, A = 10,000 × (103/100)^2
⇒ Amount, A = 10,000 × 103/100 × 103/100
⇒ Amount, A = 10,000 × 1.03 × 1.03
⇒ Amount, A = Rs 10,609
Hence, the compound interest is 10,609.
What does the question says ?
- This question says that the Principal is given as Rupees 10,000 and the rate of interest is given as 8% compounded quarterly means we have to divide 8 by 4 and we get 2. Afterwards the time is given as 6 months converted into quaters we get 6/12 × 4 = 2 quaters.
How to solve this question ?
- To solve this question we have to use the formula of compound interest that is A = P ×(1+R/100)ⁿ Now we have to put the values according to this formula. We get our final result easily and it's Rupees 10,609
Full solution :
Using formula of compound interest
↝ A = P ×(1+R/100)ⁿ
Where,
- A means amount
- P means Principal.
- R means Rate.
- ⁿ means time.
Putting the values,
↝ A = P ×(1+R/100)ⁿ
↝ A = 10,000 × (1+2/100)²
↝ A = 10,000 × (103/100)³
↝ A = 10,000 × 103 / 100 × 103 / 100
↝ A = 10,000 × 1.03 ×1.03
↝ A = 10,000 × 1.0609
↝ A = 10,609 Rs
Hence, Compounded interest is Rupees 10,609
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