Find the compound interest on ₹ 10000 for 2 years at 12% per annum.
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Answer:
A = P (1+R/100)n
= 10000 (1+12/100)2
= 10000(1+ 3/25)2
= 10000 (28/25) 2
= 10000 *28/25*28*/25
= 16*28*28
=12544
C. I = 2,544
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