Question

Find the compound interest on ₹ 10000 for 2 years at 12% per annum.​

Answer 1

Answer:

A = P (1+R/100)n

= 10000 (1+12/100)2

= 10000(1+ 3/25)2

= 10000 (28/25) 2

= 10000 *28/25*28*/25

= 16*28*28

=12544

C. I = 2,544