Question

find the compound interest on 1200 for two years at 5% p.a.​

Answer 1

Answer:

Hope this answer helps you:

Answer 2

Step-by-step explanation:

• P = 1200
• r = 5%
• t = 2 years
• n = 1 ( where n → no. of times compounded in a year)

Since we know that,

$a = p( {1 + \frac{ \frac{r}{n} }{100} })^{nt} \\ \\ = > 1200(1 + { \frac{5}{100} })^{2} \\ \\ = > 1200 \times \frac{21}{20} \times \frac{21}{20} \\ = > 1323$

Again,

We know that,

A = P + C.I.

=> C.I. = A - P = 1323 - 1200 = 123

Required C.I. is Rs. 123 for Rs.1200 for 2 years.

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