find the compound interest on 135000 for 3/2 year at 20/3% pa when compounded semi annually
and answer is 13955
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0
Answer:
Given, P=32000 Rs
R=10 % p.a
n=9 months =
4
3
year
If interest compounded quarterly,
Amount = P(1+
4×100
R
)
4n
=32000(1+
400
10
)
4×
4
3
=32000(1+0.025)
3
=34460.5Rs
Compound interest = Amount - Principal
=34460.5−32000
=Rs.2460.50
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