Question

find the compound interest on 14000 at 16%per
annum for 11/4 year​

Answer 1

Answer:

b6frcoy

Step-by-step explanation:

g5gygyhybyvth6h

Answer 2

Answer:

51805.6

Step-by-step explanation:

P = 14000, i = r /100 = 16/100 = 16, t = 11/4

A= p(1+i)^xt

A= p(1+i)^xt= 14000(1+.16)^*11/4

A= p(1+i)^xt= 14000(1+.16)^*11/4= 14000(1.16)^x11/4

A= p(1+i)^xt= 14000(1+.16)^*11/4= 14000(1.16)^x11/4= 14000×1.3456×11/4

A= p(1+i)^xt= 14000(1+.16)^*11/4= 14000(1.16)^x11/4= 14000×1.3456×11/4= 18838.4×11/4

A= p(1+i)^xt= 14000(1+.16)^*11/4= 14000(1.16)^x11/4= 14000×1.3456×11/4= 18838.4×11/4= 51805.6