Find the compound interest on ₹14000 for 1½ years at 12% per annum, if the interest is compounded half-yearly
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Answer:
rate of interest=12% per annum=6% per half year
time=1 integer 1/2
original principal=$14000
interest for the first half year=(14000×6×3/2×100)=1260
amount of the end of the first half year=14000+1260=15260
principal for the second half year=15260
interest for the second half year=(15260×6×3/ 2×100)=13734
amount at the end of the second half year =(15260+13734)=28994
Therefore, Compound interest=(28994 -14000)=14994
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COMPOUND INTEREST: (28994 - 14000) = 14994
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