Question

find the compound interest on 14000 rupees for 1 year at 10 percent per annum, the interest being compounded quarterly ​

Answer 1

Answer:

Sum (p)=Rs.12000

Rate of interest =14% per annum

Time =1 year

Since the interest is compounded half yeary.

Therefore,

R=

2

14

=7%

n=2

Therefore,

A=P(1+

100

R

)

n

⇒A=12000(1+

100

7

)

2

⇒A=

100×100

12000×107×107

=Rs.13738.8

Therefore,

Compound interest =A−P

=13738.8−12000

=Rs.1738.8

Answer 2

Hello,

P = ₹ 14000

R = 10 %

T = 3/12

Quarterly Amount = ₹ 15,400

Yearly Amount = ₹ 61,600