Question

Find the compound interest on 2,000 rupees for 1½ years at 10% p.a.,when the interest is compounded half yearly.
please help me nobi bro!​

Answer 1

$\huge\pink{⛄ Answer ⛄}$

Here, P = $12,000, R = 20% and n = 2 years.

Amount after 2 years = P ( 1 + r/2) 2n= 12,000 ( 1 + 0.20/2) 2 x 2= 12,000 ( 1 + 0.1) 4

= 12,000 (1.1) 4

= 12,000 x 1.4641

Amount = $ 17569.20

∴ C.I = A - P

C.I = 17569.20 - 12000

C.I = $ 5569.2

Hope it will help you