Find the compound interest on ₹2000 for 1.5 years at 10% per annum compounded half yearly
Answers
0.5= 5/10= 1/2= 1*6/2*6= 6/12years
...
1+6/12years= 12+6/12= 18/12
...
2000=p
compounded...half yearly..means 2 times..a year
...
means....18/12*2= 3 ans
....
Rate= 10/2= 5%
Ci= ?
= A-p
= 2000*105/100*105/100*105/100
= 2315.25
....
....
CI= A-p= 2315.25-2000= 315.25 ans...
a
n
s
w
e
r...is this correct?
Step-by-step explanation:
Amount: Rs. 2315.25
Compound Interest: Rs. 315.25
Step-by-step explanation:
Principal: Rs. 2000
Time: 1.5 years
Rate% p.a.: 10
Since the amount is compounded half yearly, rate becomes half and time gets doubled.
New Time: 1.5 × 2 → 3 years
New Rate% p.a.: 10/2 → 5
a=p*(1+r/100)n
2000 × (1 + 5/100)^3
→2000 × (1 + 1/20)^3
→2000 × [(20+1)/20]^3
→2000 × (21/20)^3
→2000 × 21/20 × 21/20 × 21/20
→2315.25
Amount: Rs. 2315.25
Compound Interest: Amount - Principal
→2315.25 - 2000
→315.25
Compound Interest: Rs. 315.25
Hence, Amount and Compound Interest are Rs 2315.25 and Rs. 315.25, respectively.
Hope it helped you...
Kindly Mark as Brainliest...
Thank you and have a nice day