Question

find the compound interest on 20000 for 3 years at 15% per annum

Answer 1

20000{(1+15/100)3-1}
20000{(100+15/100)3-1}
20000{(115/100)3-1}
(12167-8000/8000)
4167/8000*20000
=20835/2
HENCE, ANSWER IS 20835/2.
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Answer 2

HeY MatE !!

HerE IS YouR AnsweR —————

Principal = ₹ 20,000 ―――(P)

Time = 3 years ――― (n)

Rate % = 15% p.a. ――― (R)

therefore,

$A = P(1 + \frac{R}{100} ) {}^{n} \\ \\ = 20000(1 + \frac{15}{100}) {}^{3 } \\ \\ = 20000 \: ( \frac{100 + 15}{100} ) {}^{3} \\ \\ = 20000 \times \frac{115}{100} \times \frac{115}{100} \times \frac{115}{100} \\ \\ = 30417.5 \: rupees$

so, amount is ₹ 30417.5

――――――――――――――――――

now , compound interest = A- P

= 30417.50 - 20000

= ₹ 10417 .50

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