Question

find the compound interest on ₹25000 at an intrest of 10 % per annum for 2 years​

Answer 1

Step-by-step explanation:

Given:- Principal (p) = Rs. 25000

Rate of interest (r) = 10%

Time (n) = 2 years

$amount = p( {1 + \frac{r}{100} })^{n}$

$= 25000( {1 + \frac{10}{100} )}^{2}$

$= 25000( { \frac{100 + 10}{100} )}^{2}$

$= 25000( { \frac{110}{100} )}^{2}$

$= 25000 \times \frac{110}{100} \times \frac{110}{100}$

$= 30250$

Compound Interest = Amount - Principal

= Rs. (30250 - 25000)

= Rs. 5250

Answer :- The Compound Interest is Rs. 30250.

Answer 2

Before, finding the answer. Let's find out on how we can find the answer.

• To find the Compound interest we must first find the Amount by using the formula of :

$\sf{A = P + \bigg( 1 + \dfrac{R}{100} \bigg) ^T}$

• Now, we must Subtract the Amount and Principal to get the Compound Interest.

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Given :

Principal = Rs. 25000

Rate = 10 %

Time = 2

To find :

Compound Interest

Solution :

$\sf{Amount = P + \bigg( 1 + \dfrac{R}{100} \bigg) ^T}$

$\sf{= 25000 + \bigg( 1 + \dfrac{10}{100} \bigg) ^2}$

$\sf \sf{= 25000 + \bigg( \dfrac{11}{100} \bigg) ^2}$

$\sf{= 25000 \times \dfrac{11}{100} \times \dfrac{11}{100} }$

$\sf = rs. 30250$

Compound Interest = Amount - Principal

= 30250 - 25000

= Rs. 5250

Hence, Compound Interest is Rs. 5250.

____________________

Formula's Used :

$\sf{Amount = P + \bigg( 1 + \dfrac{R}{100} \bigg) ^T}$

Compound Interest = Amount - Principal