find the compound interest on 26000 for 3 years at the rate of 10percent per annul compounded annually
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compound interest
p=26000
t=3 year
r=10%
A=p (1+r/100)t
=26000 (1+10/100)3
=26000 (11/10)3
=26000×11 /10×11 /10×11 /10
=34606
p=26000
t=3 year
r=10%
A=p (1+r/100)t
=26000 (1+10/100)3
=26000 (11/10)3
=26000×11 /10×11 /10×11 /10
=34606
javu:
answer is 8606
I also know that.
please choose my answer as brainlist answer.
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