find the compound interest on 3000 at the rate of 6% for one by 1/1/2 year compound half yearly
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Answered by
4
Answer:
P=3000
R=6% per annum=3% half-yearly
T=3/2 years= 3 half -yearly
So, A=P(1+R/100) power T
A=3000(1+3/100) power 3
A=3000(103/100) power 3
A=3000×103/100×103/100×103/100
A=3278181/1000
A=3278.181
CI=A-P
CI=3278.181-3000
CI=278.181
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Answered by
36
A N S W E R :
- The compound interest is 278.181.
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