Find the compound interest on 39000 invested for 2 years at the rate of 10 p.c.p.a?
Answers
Given :-
Principal amount is Rs 39,000
Rate of interest is 10 pcpa
Time is 2 years
To Find :-
Compound Interest
Solution :-
~Here, we’re given the principal , rate of interest and time for which the money is invested and we need to find the Compound Interest ( CI ) after the given time. We can easily find the amount by putting the values in it’s formula and then Compound Interest.
_____________
Here,
• The principal ( P ) is Rs. 39,000
• The rate ( R ) is 10 %
• The time ( n ) is 2 years
• The amount will be ( A )
• Compound Interest be ( CI )
_____________
As we know that ,
Finding the Amount :-
Finding the Compound Interest :-
_____________
Hence,
- The compound interest is Rs. 8,190
Step-by-step explanation:
Principal amount (P) = Rs.39000
Rate of interest (R) = 10%
Time period (T) = 2 years
Mode of compounding = Annually
In order to find the compound interest when the principal amount is compounded annually, we need to implement the formula given below:
⟹A=P(1+R/100)^n
Applying the formulae into the equation:
⟶A=39000(1+10/100)^2
⟶A=39000(1+1/10)^2
⟶A=39000×10/11×10/11
⟶A=390×11×11
⟶A=390×121
⟶A=47,190
The total amount is Rs.47,190.
Now, in order to find the C.I amount:
⟹C.I=A−P
Applying the values into the formula:
⟶C.I=47,190-39000
⟶C.I=8,190
Therefore, the Compound interest amount is Rs.8,190