Find the compound interest on ₹4000 for 2 1/2 years at 10% per annum?
Answers
Answered by
1
Answer:
Step-by-step explanation:
P=4000
R=10%
Times =2.5 years
First take n=2 years
A=P(1+
100
r
)
n
=4000(
10
11
)
2
4000(
100
121
)
A=4840
Simple interest for last
2
1
years is
100
PRT
=
100
4840×10
×
2
1
=242
Amount after 2
2
1
year =4840+242
=5082
Compound interest =5082−4000
CI=1082.
Answered by
0
Answer:
According to our question, P=4000,r=10%,n=2years. On Calculation A we get, A=P(1+r100)n⇒A=4000(1+10100)2⇒A=P(1+110)2⇒A=4000(1110)2⇒A=4000×121100⇒A=4840 Rs. Hence the amount after 2 years will be 4840 and it'll only work as the principal amount for simple interest.
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