Question

find the compound interest on 4000 for 2.5 years at 10 per annum

Answer 1

SI for the 1st year
(4000*1*10)/100
=400
A=4000+400
4400
SI for 2nd year
(4400*1*10)/100
=440
A=4400+440
4840
SI for 1/2year
(4840*1/2*10)/100
242
A =4840+242
5082
Now CI=5082-4000
1082