Question

Find the compound interest on ₹5000 with the rate of 20% for 1.5 years

Answer 1

Answer:

788.125

Explanation:

Given :

• Principal p= Rs.5000

• Rate of interest r= 10% =0.1

• No. of compounds per year = n = 2

To Find :

• Compund Interest

Solution :

$\sf{A}=P\bigg(1+\dfrac{r}{n}\bigg)^{nt}$

So,

$\dasharrow\sf{} A=5000\bigg(1+\dfrac{0.1}{2}\bigg)^{2\times1.5}$

$\dasharrow \sf{A}=5000\bigg(1.05\bigg)^{3}$

$\dasharrow \sf{A}=$ ₹$\sf{}5788.125$

Compund Formula(CI) Formula =>

$\boxed{\sf{Compound\ interest = Amount - Principal}}$

$\dasharrow \sf{CI}= 5788.125-5000$

$\dasharrow \sf{CI =}$ ₹$.788.125$

Answer 2

Answer:

  $\\ \: \: \: \longrightarrow \: \: \: \large{ \boxed { \bold{red \answer \overrightarrow{answer}}}}$

5000(1+5/100)^3

=5000(1+1/20)^3

=5000(21/20)^3

=5000x9261/8000

=5788.12(app.)

compound interest=5788.12-5000=788.12

Step-by-step explanation: