Math, asked by swapnajamuneshwar44, 3 months ago

find the compound interest on 8500Rs. for 2 years at 8% p.a​

Answers

Answered by Anonymous
2

 \huge \sf \underline \red{Answer : }

 \:  \:  \:  \:  \:  \:  \: \sf  \underline \pink{    -12837}

 \sf \huge \underline \blue{Given : }

  • principal = 8500
  • rate = 8 %
  • t = 2 years

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \underline{we \: know \: that \: interest \: formula}

 \:  \:  \:  \:  \:  \:  \:  \sf { \boxed{\underline{ \underline {\red{ \tt{interest \: for \: 1st \: year =  \frac{p \times r \times t}{100}}}}}}}

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \implies \sf{ \dfrac{8500 \times 8 \times 2}{100}}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \implies \sf{  = 1360}

 \sf \underline{ \therefore \: amount \: of \: first \: year \: is \: 8500 + 1360 }

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \underline{ = 9860}

 \sf \underline \blue{ \: so \: now \: interest \: of \: 2nd \: year \: is \: 9860}

\:  \:  \:  \:  \:  \:  \:  \sf { \boxed{\underline{ \underline {\red{ \tt{interest \: for \: 2nd\: year =  \frac{p \times r \times t}{100}}}}}}}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \implies \sf \blue{ \dfrac{9860\times 8 \times 2}{100}}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \implies \sf \blue{  = 1577.6}

\sf \underline \blue{ \therefore \: amount \: of \: second \: year \: is \: 9860 +1577.6  }

 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \sf \underline \blue{ = 11437.6}

\:  \:  \:  \:  \:  \:  \:  \sf { \boxed{\underline{ \underline {\red{ \tt{interest \: for \: 3rd\: year =  \frac{p \times r \times t}{100}}}}}}}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \implies \sf { \dfrac{11437.6\times 8 \times 2}{100}}

\:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \implies \sf{  = 1830}

\sf \underline{ \therefore \: amount \: of \: third\: year \: is \:11437 + 1830 }

=12367

  \:  \:  \:  \:  \: \sf \underline{we \: know \: that \: c.i \: formula}

  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \sf{ \boxed{ \underline{ \underline{  \purple{ \tt{ci = amount - principal \: }}}}}}

  • ci compound interest

  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: \sf{(12367 - 8500) = 3867}

 \:  \:  \:  \sf \underline{ \: now \: total \: compound \: interest}

 \sf{ \boxed{ \underline{ \underline{  \purple{ \tt{total \: ci = interest \: for \: 1st \: year + 2nd \: year + 3rd \: year }}}}}}

  \:  \:  = \sf{1360 - 1830 - 12367 =  - 12837}

 \sf \underline \pink{ \therefore  \:  -12837}

Answered by vidhyabarud
1

Answer:

CI = Rs 1414.4

Step-by-step explanation:

Given :

Principal = Rs 8500

Rate of Interest = 8% p.a

Time = 2 yrs

To Find :

Compound Interest

Formula Used :

CI = A - P

CI = P ( 1 + R / 100 ) ^ n - P

Procedure :

8500 ( 1 + 8 / 100 ) ^ 2 - 8500

8500 ( 108 / 100 ) ^ 2 - 8500

8500 * 108 / 100 * 108 / 100 - 8500

17 * 54 * 54 / 5 - 8500

17 * 2916 / 5 - 8500

49572 / 5 - 8500

9914.4 - 8500

= 1414.4

Solution :

Compound Interest = Rs 1414.4

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