Find the compound interest on a 12,000
at rate of interest of 12% for one
year if the interest is being
compounded half yearly
Answers
Answered by
1
Answer:
Step-by-step explanation:
Solution
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Here P=12,000 Rs., n=2 years, R=10
Amount(A)=P(1+
100
R
)
n
=12000(1+
100
10
)
2
=12000(
10
11
)
2
=
100
12000×121
=14,520 Rs.
Compound interest(C.I)=A−P=14,520−12,000=2520
Hence, the compound interest is Rs. 2,520
Answered by
2
12000 × (1 + 10/100)^2×1.5
12000 × (1.1)³
12000 × 1.331
= 15972 is correct answer
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