Question

find the compound interest on a sum of ₹12,000 at the rate of 8 per cent for 1 year compounded quaterly. ​

Answer 1

Answer:

CI = 12000x(102/100) 4-12ooo

=12989-12ooo = Rs. 989

Answer 2

Answer:

P=Rs.12,000   R=8%   T=1yr  

CI= P(1+R/400)4n   where P is the amount, R is the rate and N is the time or the number of years.

Step-by-step explanation:

∴ 12000×(1+8/400)^(4×1)

= 12000×(1+1/50)^4

=12000×(51/50×51/50×51/50×51/50)

=12000×6765201/6250000

You can simplify 12000 and 6250000 by cutting out the zeroes.

this leaves you with: 12×6765201/6250

Now you can further simplify 6250 and 12 by dividing by 2 on both sides.

This leaves you with 3125 and 6.

Now you get 6×6765201/3125

so by multiplying 6 and 6765201 you get 40591206.

so the final step is 40591206/3125.

by dividing these you get 12989.18 (approx.)

therefore the amount is 12989.18Rs. and the Compound interest is Rs.989.18.

I hope this helps you...