Question

Find the compound interest on a sum of Rs.8000 at 10%per annum for 3 years compounded annually.​

Answer 1

Step-by-step explanation:

$Compound\: Internet = P((1 + \frac{r}{100} )^{2} - 1) \\ = 8000 ((1 + \frac{10}{100} )^{2} - 1) \\ = 8000(( \frac{10 + 1}{10} )^{3} - 1) \\ =8000( \frac{1331}{1000} - 1) \\ = 8000( \frac{1331 - 1000}{1000} ) \\ = 8000 \times \frac{331}{1000} \\ = 8 \times 331 \\ = 2, 648 \\ \blue{\boxed{Compound \: Internet = ₹ \: 2,648}}$