Question

Find the compound interest on As. 15000 for two years at 8% p.
a

Answer 1

Given

P=₹15000

T=2yr

R=8%p.a.

$amount = p(1 + \frac{r}{100}) ^{t}$

$a = 15000(1 + \frac{8}{100} ) ^{2}$

$a = 15000 \times( \frac{108}{100} ) ^{2}$

$a = 15000 \times \frac{108}{100} \times \frac{108}{100}$

A=17496

Ci=A-P

Ci=17496-15000

Ci=2496

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Answer 2

Hello..
Answer...

$here \: principal \: = rupees \: 15000 \\ time = 1year \\ rate \: of \: nterest = 8\%p.a \\ smiple \: interest = \frac{p \times r \times t}{100} \\ = rupees \frac{15000 \times 1 \times 8}{100} \\ = rupees1200$
Interest for the first year, the amount in the first year becomes the principal here.

so we have,
Principal = rupees 16,200
Time = 1 year
Rate of interest =8% p.a
$simple \: interest \: = rupees \: \frac{16200 \times 1 \times 8}{100} \\ = rupees \: 1296$
so, Compound interest for two years = 1200+1296= rupees 2496.

Hope it helped.
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