Question

find the compound interest on principal 10,000 rate 12% and time 2 years

Answer 1

P=10,000 R=12% T=2 years

A=P (1+R/100)to the power n

A= 10000×(1+12/100)×(1+12/100)

A=10404

CI=A-P

=10404-10000

=404

Answer 2

Hey mate here is Ur ans

$p = 10000 \: \: \: \: r = 12\% \: \: \: t (n)= 2yrs \\ \\ formula \: for \: compound \: interest \\ c = p(( {1 + r)}^{n} - 1) \\ c = 10000(( {1 + \frac{12}{100}) }^{2} - 1) \\ c = 10000(( {1 + 0.12)}^{2} - 1) \\ c = 10000(( {1.12)}^{2} - 1) \\ c = 10000(1.2544 - 1) \\ c = 10000(0.2544) \\ c = 2544$

I hope this will helps you

mark my ans as brainliest