Question

Find the compound interest on Rs 10,000 at 8 % per annumfor 2 years.​

Answer 1

Given

• Principal= ₹ 10,000
• Rate= 8%
• Time = 2 year's

To Find

• Compound Interest

Formula Used

$\sf \: CP = p \{(1 + \frac{r}{100} )^{n} - 1 \}$

• On Putting The value Of Principal, Rate And time In Formula. We get,

$~~\sf \: CP = 10000 \{\left( 1 + \dfrac{8}{100} \right) ^{2} - 1 \}$

$~~\sf \: CP = 10000 \{\left(\dfrac{108}{100} \right) ^{2} - 1 \}$

$~~\sf \: CP = 10000 \left(\dfrac{11664}{10000} - 1 \right)$

$~~\sf \: CP = 10000 \left(\dfrac{11664 - 10000}{10000} \right)$

$~~\sf \: CP = \cancel{10000} \times \dfrac{1664 }{ \cancel{10000}}$

$~~~~\underline{\boxed{\sf \: CP = ₹ \: 1664}}$

• the compound interest on Rs 10,000 at 8 % per annum for 2 years Is ₹ 1664.

Answer 2

Step-by-step explanation:

compound interest is 1664

hope this helps you