find the compound interest on rs 10000 for 12 months at 10% per annum, if the intrest is compounded a) annually b) halfyearly
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Answers
Given:-
- Principal = ₹10000
- Time = 12 months = 1 year
- Rate = 10% p.a.
To Find:-
Compound interest if the interest is compounded:-
- a) annually
- b) half yearly
Solution:-
a) Compounded annually
→ We know,
- A = P(1 + r/100)ⁿ
Hence,
Let us calculate the amount first.
= A = 10000(1 + 10/100)¹
⇒ A = 10000(1 + 1/10)¹
⇒ A = 10000(11/10)¹
⇒ A = 10000 × 11/10
⇒ A = 11000
∴ Amount of the interest is compounded annually is ₹11000
Now,
Let us calculate CI
We know,
- CI = Amount - Principal
Hence,
CI = 11000 - 10000
⇒ CI = ₹1000
∴ CI after 1 year if the interest is compounded annually will be ₹1000.
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b) Compounded half-yearly
→ We know,
- A = P(1 + r/200)²ⁿ
Hence,
= A = 10000(1 + 10/200)²*¹
⇒ A = 10000(1 + 1/20)²
⇒ A = 10000(21/20)²
⇒ A = 10000 × 21/20 × 21/20
⇒ A = 11025
∴ Amount if the interest is compounded half-yearly is ₹11025.
Now,
Let us calculate the CI
CI = 11025 - 10000
⇒CI = 1025
∴ The compound interest is the interest is compounded half-yearly will be ₹1025.
________________________________
Answer:
Given
Principal - rs 10000
Time - 12 month's
Rate - 10%
To find
a) annually
b) half-yearly
We know that:-
Amount = P(1 + )t
We have interest compounded half-yearly
thus, Time = 2 × (year's) = 2 rate
= = 5 it means 5% interest after every six months
Formula to find interest:-
interest will be A = P(1 + t×2
According to Question:-
Amount = p)t
= 5 and time = = 2
it means that the men will get an interest of 5% after every 6 month's
Total amount, P(1 + )t
)²
)²
=
= 105×105
=11025
The total amount = Rs.
★Now, Compound interest = (total amount) - (principal amount)
- total amount - Rs.11025
- Principal amount - Rs.10000
Rs. 11025 - 10000
= Rs.1025
The Compound interest =