Math, asked by helloashmita, 1 year ago

find the compound interest on rs 11200 at 17 1/2 % pa for 2 years

Answers

Answered by siddhartharao77
12

Answer:

4263

Step-by-step explanation:

Given, P = 11200,R = 17 1/2% = 35/2%, Time = 2 years.

We know that A = P(1 + r/100)ⁿ

= 11200(1 + 35/200)²

= 11200(1 + 7/40)²

= 11200(47/40)²

= 11200(2209/1600)

= (11200 * 2209)/1600

= 15463.


Now,

Compound Interest = A - P

                                 = 15463 - 11200

                                 = 4263



Therefore, Compound Interest = 4263.


Hope it helps!


siddhartharao77: :-)
helloashmita: thanks
siddhartharao77: Thanks!
Answered by Siddharta7
4

Step-by-step explanation:

Given

Principal =₹11200

rate = 17 \frac{1}{2} \%

Rate =35/2 %

Time =2yr

As we know Amount=P(1+R/100)^t

=11200(1+37/200)²

=11200x237/200x237/200

=₹15727.32

Compound interest = Amount - principal

Ci=15727.32-11200

Ci=₹4527.32

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