Question

Find the compound interest on Rs.12,500 at 10% per annum for 3 years

Answer 1

Hey there !!


Given :-

→ P = ₹ 12,500 .

→ R = 10% .

→ t = 3 years.


To find :-

→ CI ( compound interest ) .


▶ Solution :-

°•° A = P( $1 + \frac{R}{100}$ )^t .

= 12500( $1 + \frac{10}{100}$ )³ .

= 12500( $1 + \frac{1}{10}$ )³ .

= 12500( $\frac{ 10 + 1 }{10}$ )³ .

= 12500( $\frac{11}{10}$ )³ .

= 12500 × $\frac{1331}{1000}$ .

•°• A = 16637.5 .


Therefore, compound interest = A - P.

= 16637.5 - 12500 .

= 4137.5 .


✔✔ Hence, it is solved ✅✅.

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THANKS


#BeBrainly.

Answer 2

Question;

Find the compound interest on Rs.12,500 at 10% per annum for 3 years.

Method of Solution;

Given;

Principal = 12,500

Rate = 10%

Time = 3 years

To find ;

Amount = ? and Compound Interest = ?

According to the Question!

Using Formula of Compound Interest

$A = p(1 + { \frac{r}{100} )}^{t} \\ \\ \\ \\ 12500(1 + { \frac{10}{100} )}^{3} \\ \\ \\ 12500 {( \frac{100 + 10}{100} )}^{3} \\ \\ \\ 12500( { \frac{110}{100}) }^{3} \\ \\ \\ 12500( \frac{ 1331,000}{ 1,000,000 } ) \\ \\ \\ 12500 \times 1.331 \\ \\ 16,637.5$

ATQ;

Compound Interest = Amount- Principal

=> Compound Interest = 16,637.5- 12,500

=> 4,137.5

Hence, Compound Interest = 4,137.5