Math, asked by sparshsinghal023, 1 day ago

find the compound interest on rs 12000 at 8% p.a. for 2 1/2 years. the interest is payable half-yearly.

Answers

Answered by sudarshanchauhan409
2

Answer:

Here P=12,000 Rs., n=2 years, R=10

Amount(A)=P(1+

100

R

)

n

=12000(1+

100

10

)

2

=12000(

10

11

)

2

=

100

12000×121

=14,520 Rs.

Compound interest(C.I)=A−P=14,520−12,000=2520

Hence, the compound interest is Rs. 2,520

Answered by IIMrSAURAVII
3

Answer:

Here P=12,000 Rs., n=2 years, R=10

Amount(A)=P(1+100R)n

                     =12000(1+10010)2

                     =12000(1011)2

                     =10012000×121

                     =14,520 Rs.

Compound interest(C.I)=A−P=14,520−12,000=2520

Hence, the compound interest is Rs. 2,520

Similar questions