Math, asked by kamilibhavani, 1 day ago

find the compound interest on Rs.12000 for 3years at 10% per annum compounded annually

Plz answer fastly​

Answers

Answered by ImperialGladiator
35

Answer:

  • Compound interest = Rs.3972

Explanation:

We know,

→ C.I. = Amount - principal

Using amount formula,

 \implies \rm \: A = p \bigg(1 +  \dfrac{r}{100}  \bigg)^{n}

Where,

  • p(principal) = Rs.12,000
  • r(rate) = 10% p.a.
  • n(time) = 3 yrs.

Substitute the given values,

 \rm = 12000\bigg(1 +  \dfrac{10}{100}  \bigg)^{3}

 \rm = 12000\bigg(1 +  \dfrac{1}{10}  \bigg)^{3}

 \rm = 12000\bigg( \dfrac{11}{10}  \bigg)^{3}

 \rm = 12000 \times  \dfrac{1331}{1000}

 \rm = 12 \times 1331

 = 15972

Compund interest :-

 = 15972 - 12000

 = 3972

Required answer: Rs.3972

__________________________________________

Answered by StarFighter
24

Answer:

Given :-

  • A sum of Rs 12000 for 3 years at 10% per annum compounded annually.

To Find :-

  • What is the compound interest.

Solution :-

First, we have to find the amount :

As we know that :

\bigstar \: \: \sf\boxed{\bold{A =\: P\bigg(1 + \dfrac{r}{100}\bigg)^n}}\: \: \: \bigstar\\

where,

  • P = Principal
  • A = Amount
  • r = Rate of Interest
  • n = Time Period

So,

Given :

  • Principal = Rs 12000
  • Rate of Interest = 10%
  • Time Period = 3 years

According to the question by using the formula we get,

\implies \sf A =\: 12000\bigg(1 + \dfrac{10}{100}\bigg)^3\\

\implies \sf A =\: 12000\bigg(\dfrac{100 \times 1 + 10}{100}\bigg)^3\\

\implies \sf A =\: 12000\bigg(\dfrac{100 + 10}{100}\bigg)^3\\

\implies \sf A =\: 12000\bigg(\dfrac{110}{100}\bigg)^3\\

\implies \sf A =\: 12000\bigg(\dfrac{110}{100} \times \dfrac{110}{100} \times \dfrac{110}{100}\bigg)\\

\implies \sf A =\: 12000\bigg(\dfrac{110 \times 110 \times 110}{100 \times 100 \times 100}\bigg)\\

\implies \sf A =\: 12000\bigg(\dfrac{1331000}{1000000}\bigg)\\

\implies \sf A =\: 12000 \times \dfrac{1331\cancel{000}}{1000\cancel{000}}\\

\implies \sf A =\: 12{\cancel{000}} \times \dfrac{1331}{1\cancel{000}}\\

\implies \sf A =\: 12 \times 1331\\

\implies \sf\bold{A =\: Rs\: 15972}\\

Hence, the amount is Rs 15972 .

Now, we have to find the compound interest :

As we know that :

\bigstar \: \: \sf\boxed{\bold{Compound\:  Interest =\: A - P}}\: \: \: \bigstar\\

where,

  • A = Amount
  • P = Principal

Given :

  • Amount = Rs 15972
  • Principal = Rs 12000

According to the question by using the formula we get,

\dashrightarrow \sf Compound\: Interest =\: Rs\: 15972 - Rs\: 12000\\

\dashrightarrow \sf\bold{Compound\: Interest =\: Rs\: 3972}\\

\therefore The compound interest is Rs 3972 .

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