Find the compound interest on Rs 15000 in 3 years when the rate of interest for successive years is 12%, 10% & 8% respectively.
Answers
Answered by
1
Step-by-step explanation:
Simple Interest I=
100
PNR
Here for first year,
P=Rs.15,000
N=1 year
R=6 %
So, Interest at the end of 1st year I=
100
15,000×1×6
=Rs.900
And for second year,
P=Rs.15,000+Rs.900=Rs.15,900
N=1 year
R=8%
I=
100
15,900×1×8
=Rs.1272
And, for third year,
P=Rs.15,900+Rs.1,272=Rs.17,172
N=1 year
R=10%
I=
100
17,172×1×10
=Rs.1,717.2
So, total interest =Rs.900+Rs.1,272+Rs.1,717.2=Rs.3,889.20
aggarwalanish:
bahi compound interest kya hai
Compound interest is the addition of interest to the principal sum of a loan or deposit, or in other words, interest on interest. It is the result of reinvesting interest, rather than paying it out, so that interest in the next period is then earned on the principal sum plus previously accumulated interest.
okkk
okk thx
Answered by
0
Step-by-step explanation:
P=₹15000
R%=12%,10%,8%
A=[p(1+r1/100)(1+r2/100)(1+r3/100)]
=[15000(1+12/100)(1+10/100)(1+8/100)]
=[15000(112/100)(110/100)(108/100)]
=[15000(112/100*110/100)(108/100)]
=[15000(14/125*108/100)]
=[15000(378/3125)]
=(15000*378/3125)
=₹1814.5
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