Find the compound interest on Rs 15625 for 3 years at 12% per annum compounded annually
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1
Answer:
The amount is 21952 and interest is 6327.
Step-by-step explanation:
Principal amount (P)= 15625
Rate of interest (r) = 12%= 0.12
Time (t) = 3 years.
A=P(1+r)^tA=P(1+r) t
A=15625(1+0.12)^3=21952A=15625(1+0.12)
3
=21952
The amount is 21952.
A=P+IA=P+I
A-P=IA−P=I
21952-15625=I21952−15625=I
6327=I6327=I
Therefore the amount is 21952 and interest is 6327.
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Step-by-step explanation:
A = p(1+r)^n
p=15625
r=12%
n=3
A=15625(1+12%)³
=15625 × 1.12³
=21952
CI = A-P
=21952-15625
=6327
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