find the compound interest on Rs 18000 at 10% per annum for 3 one-third years
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C.I. = p(1+r÷100)n
18000( 1+ 10÷100) power is 10
18000(1+1÷10) power of 10
18000× (11÷10) power of 10
18000× (121÷100)
180×121 = 21780
18000( 1+ 10÷100) power is 10
18000(1+1÷10) power of 10
18000× (11÷10) power of 10
18000× (121÷100)
180×121 = 21780
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