Question

find the compound interest on Rs. 20,000 for 3 years at 10% annum.​

Answer 1

₹6,620

Step-by-step explanation:

$a = p(1 + \pi \div 100) {}^{2}$

p=20,000

r=10%

n=3 years

a=20,000(1+10÷100)³

=20,000×110÷100×110÷100×110÷100

a=26,620

C.I=A.P

=26,620−20,000

=6,620Rs.

Answer 2

Answer:

A=P(1+π/100)n

P= 20,000

R= 10%

n= 3 years

A = 20,000 (1+10/100)³

=  20,000x 11/10 x 11/10 x 11/10

A = 26,620

C.I = A.P.

=  26,620-20,000

=  6,620 Rs.

Step-by-step explanation:

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