find the compound interest on rs.24000 compounded semi-annually for 1 1/2 years at the rate of 10% per annum
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nivihelana:
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Answered by
9
Answer:
3783 rupees
Step-by-step explanation:
as the rate is compounded semi annually for one and a half years. there will be 3 half year and rate is also half =5%
given that
p=24000
r=5%
n=3
as we know
[tex]A=P (1+\frac{r}{100})^{n}\\\\A=24000(1+\frac{5}{100})^{3}\\\\A=24000(1+\frac{1}{20})^{3}\\\\A=24000(\frac{21}{20})^{3}\\\\A=27783{/tex}
as A= P+I
so I=A-P
I=27783-24000
I=3783 rupees
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