Question

Find the compound interest on rs.25000 at rate of 12 percent per annum for three years

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Compound\:Interest=10,123.2\:rupees}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given: }} \\ \tt: \implies Principal(p) = 25,000 \: rupees \\ \\ \tt: \implies Rate\%(r) = 12\% \\ \\ \tt: \implies Time(t) = 3 \: years \\ \\ \red{\underline \bold{To \: Find: }} \\ \tt: \implies Compound \: Interest = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies A = p(1 + \frac{r}{100} )^{t} \\ \\ \tt: \implies A =25000(1 + \frac{12}{100} )^{3} \\ \\ \tt: \implies A =25000 \times (1 + 0.12)^{3} \\ \\ \tt: \implies A=25000\times (1.12)^{3} \\ \\ \tt: \implies A = 25000 \times 1.404928 \\ \\ \green{\tt: \implies A =35,123.2 \: rupees} \\ \\ \bold{For \: compound \: Interest} \\ \tt: \implies C.I = A - p \\ \\ \tt: \implies C.I= 35123.2 - 25000 \\ \\ \green{\tt: \implies C.I =10,123.2 \: rupees}$

Answer 2

Answer:

Given:

• 25000 = Compound interest.

• 12 = Rate % .

• 3 years = Time.

Find:

• Find the compound interest.

Know terms:

• (CI) = Compound interest.

• (A) = Amount.

• (R) = Rate.

• (T) = Time.

• (n) = number if years (n3).

According to the question:

⇒ A = P (1 + R/100)^n

⇒ A = 25000 (1 + 12/100)^3

⇒ A = 25000 × (1 + 0.12)^3

⇒ A = 25000 × (1.12)^3

⇒ A = 25000 × 1.404928

⇒ A = 35123.2 ₹

Calculating for compound interest:

⇒ CI = A - P

⇒ 35123.2 - 25000

⇒ 10123.2 rupees.

Therefore, 10123.2 rupees is the compound interest.