Question

find the compound interest on rs 26000 for 3 years at the of 10% per annum compound annually

Answer 1

Given
P=₹26000
R=10%
T=3yr


$a = p \: (1 + \frac{r}{100} )^{t}$

$a = 26000 {(1 + \frac{10}{100}) }^{3}$

$a = 26000 { (\frac{11}{10} )}^{3}$

$a = 26000 \times \frac{1331}{1000}$

A=26x1331

A=₹34606

Compound interest = amount - principal

Ci=34606-26000

Ci=₹8606


This is ur ans hope it will help you

Answer 2

Answer:

P= 26,000; R= 10% p.a. ; n=3 yrs

$a = p(1 + \frac{r}{100})^{n} \\ 26000(1 + \frac{10}{100} )^{3} \\ 26000( \frac{11}{100})^{3} \\ 26000 \times \frac{11}{10} \times \frac{11}{10} \times \frac{11}{10} \\ = 26 \times 11 \times 11 \times 11 = 34606 \: rs.$

Therefore,C.I. = A-P = 34606-26000= 8606 rupees.