Question

find the compound interest on rs.3600 at 10%for annum per 3 years compounded annually.​

Answer 1

Answer:

1191.6

Step-by-step explanation:

A = P (1+R÷100)³

  = 3600 (110÷100)³

  = 3600×11÷10×11÷10×11÷10

  = 4791.6

C.I = 4791.6 - 3600

   = 1191.6

Answer 2

Solution :

$\underline{\bf{Given\::}}}}$

• Principal, (P) = Rs.3600
• Rate, (R) = 10% p.a
• Time, (n) = 3 years

$\underline{\bf{Explanation\::}}}}$

Using formula of the compounded annually :

$\boxed{\bf{Amount=Principal\bigg(1+\frac{R}{100} \bigg)^{n}}}}$

$\longrightarrow\sf{A=3600\bigg(1+\cancel{\dfrac{10}{100} }\bigg)^{3}}\\\\\\\longrightarrow\sf{A=3600\bigg(1+\dfrac{1}{10} \bigg)^{3}}\\\\\\\longrightarrow\sf{A=3600\bigg(\dfrac{10+1}{10} \bigg)^{3}}\\\\\\\longrightarrow\sf{A=3600\bigg(\dfrac{11}{10} \bigg)^{3}}\\\\\\\longrightarrow\sf{A=36\cancel{00}\times \dfrac{11}{\cancel{10}} \times \dfrac{11}{\cancel{10}} \times \dfrac{11}{10} }\\\\\\\longrightarrow\sf{A=\dfrac{36\times 11\times 11\times 11}{10} }$

$\longrightarrow\sf{A=\cancel{\dfrac{47916}{10} }}\\\\\longrightarrow\bf{A=Rs.4791.6}$

Now;

We know that compound Interest :

$\longrightarrow\sf{C.I.=Amount-Principal}\\\\\longrightarrow\sf{C.I.=Rs.4791.6-Rs.3600}\\\\\longrightarrow\bf{C.I.=Rs.1191.6}$