Question

Find the compound interest on rs 80000 for 3 years if the rates for the 3 years are ,5%, 4% and 5% respectively.

Answer 1

Answer:

amount is 91728 and the compound intrest is 11728

Step-by-step explanation:

solution------>

Given:-

• P=80000
• time =3 years
• R1 =5%
• R2=4%
• R 3 = 5%

as per given condition

$a = p \times (1 + \frac{r1}{100} )(1 + \frac{r2}{100} )(1 + \frac{r3}{100} ) \\ \\ a = 80000\times (1 + \frac{5}{100} )(1 + \frac{4}{100} )(1 + \frac{5}{100} ) \\ \\ \\ a = 80000 \times \frac{105}{100} \times \frac{104}{100} \times \frac{105}{100} \\ \\ a = \frac{8 \times 105 \times 104 \times 105}{100} \\ \\ a = \frac{9172800}{100} \\ \\ a \: = 91728 \\ \\ c.i = a - p \\ \\ c.i = 91728 - 80000 \\ \\ c.i = 11728$

thus

amount is 91728 and the compound intrest is 11728

Answer 2

Dear Student,

● Answer -

Compound interest = Rs. 11728

◆ Explanation -

For first year,

Total = P × t × (100+r)/100

Total = 80000 × 1 × (100+5)/100

Total = Rs 84000

For second year,

Total = P × t × (100+r)/100

Total = 84000 × 1 × (100+4)/100

Total = Rs. 87360

For third year,

Total = P × t × (100+r)/100

Total = 87360 × 1 × (100+5)/100

Total = Rs. 91728

Compound interest over 3 years is -

Compound interest = 91728 - 80000

Compound interest = Rs. 11728

Thanks dear...