Question

find the compound interest on Rs 90000 for 3 years at the rate of 10 % per annum​

Answer 1

Answer:

29790

Step-by-step explanation:

CI = P (1 + R/100)ⁿ - P

P=90000

R=10

n=3

CI = 90000 (1+10/100)³ -90000

CI = 90000(11/10)³ - 90000

CI = 90000 X 1331/1000 - 90000

CI = 1331 X 90 -90000

CI = 119790 - 90000

CI = 29790

Answer 2

Answer:

Rs.29790

Step-by-step explanation:

Principal=90000

Time or n=3 years

Rate=10%

A= P(1+$\frac{R\\}{100}$)$^{n}$

A=90000($\frac{100+10}{100}$)$^{3}$

A= 90000 * $\frac{110}{100}$ *$\frac{110}{100}$ * $\frac{110}{100}$

A=119790

CI=119790-90000=29790