Question

find the compound interest on rs1250000 for 2years at 20% p. a compounded half yearly​

Answer 1

Answer:

P=1250000

R=20%

T=4 ( 4 HALF YEARS IN 2 Years)

A=P(1+R/100)^T

A=1250000(1+20/100)^4

1250000=(12/10)^4

1250000*12/10*12/10*12/10*12/10

125*12*12*12*12

2592000

A=2592000

CI=A-P

2592000-1250000

1342000

COMPOUND INTEREST=1342000

Answer 2

Answer:

A = P ( 1 + r/2)2n and C.I = A - P

where, P = principal

R = rate in percent p.a.( per annum i.e. annually)

n = number of years.

Examples :

1) Compute the compound interest on $12,000 for 2 years ate 20% p.a. when compounded half-yearly.

Solution :

Here, P = $12,000, R = 20% and n = 2 years.

Amount after 2 years = P ( 1 + r/2) 2n

= 12,000 ( 1 + 0.20/2) 2 x 2

= 12,000 ( 1 + 0.1) 4

= 12,000 (1.1) 4

= 12,000 x 1.4641

Step-by-step explanation:

I have written 12,000 but have to write 1250000 and solve your self .