Question

Find the compound interest on Rs15625 for 3/2years at 8% per annum when compounded half yearly.​

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

Solution

Principal = ₹15,625

Time = 3/2 years =

Rate = 8%

$\sf{A = P\bigg(1 + \dfrac{R}{200}\bigg)^{2n}}$

$\rm{ = 15625 \bigg(1 + \dfrac{8}{200} \bigg)^{2 \times \frac{3}{2} = 3} }$

$\rm{ = 15625 \bigg(1 + \dfrac{1}{25} \bigg)^{3} }$

$\rm{ = 15625 \bigg(\dfrac{25 + 1}{25} \bigg)^{3} }$

$\rm{ = 15625 \bigg(\dfrac{26}{25} \bigg) ^{3} }$

$\rm{ = 15625 \times \dfrac{(26)^{3} }{(25)^{3} } }$

$= \cancel{15625} \times\dfrac{17576}{ \cancel{15625}}$

$\sf\bf{Amount=₹17,5,76.}$

C.I. = Amount - Original Principal

C.I. = 17576 - 15625

C.I. = ₹1,951.

Therefore, Compound Interest is ₹1,951.

Additional Information

When compounded annually

$\sf{A = P\bigg(1 + \dfrac{R}{100}\bigg)^{n}}$

When compounded quarterly

$\sf{A = P\bigg(1 + \dfrac{R}{400}\bigg)^{4n}}$

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