find the compound interest on rupee 6000 for 2½ years at the rate of 10% p.a. compounded annually.
Answers
Given :
- P = Rs 6000
- R = 10%
- n =2½years
To find :
- Compound Interest
formula used :
- The formula to find the compound interest compounded annually is given by
therefore,
- The C.I is (15,246 - 6000)
= ₹ 9246.
Information provided with us :
- There are Rs.6000 who is compounded annually for 2½ years at the rate of 10% p.a. .
What we have to calculate :
- Compound Interest on that sum of rupees
Using Formulas :
Amount:-
- A = P (1 + R/100)^n
Here,
- A is amount
- P is principal
- R is rate of interest
- n is number of years
Compound Interest:-
- C.I. = A - P
Here,
- C.I. is compound interest
- A is amount
- P is principal
Performing Calculations :
- Here we have principal that is Rs.600
- no. of years are 2 and 1/2 because there's an half year also.
- Rate of interest is 10%
Putting the required values :
=> A = 6000 × (1 + 10/100)² × (1 + 10/100 × 1/2)
=> A = 6000 × (1 + 10/100)² × (1 + 5/100)
=> A = 6000 × (1×100 + 10 / 100)² × (1 + 5/100)
=> A = 6000 × (100 + 10 / 100)² × (1 + 5/100)
=> A = 6000 × (110 / 100)² × (1 + 5/100)
=> A = 6000 × (11/10)² × (21/20)
=> A = 6000 × (11 × 11 / 10 × 10) × (21/20)
=> A = 6000 × (121 / 100) × (21/20)
=> A = 600 × (121/ 10) × (21/20)
=> A = 60 × (121/ 1) × (21/20)
=> A = 60 × 121 × (21/20)
=> A = 6 × 121 × (21/2)
=> A = 3 × 121 × 21
=> A = 121 × 63
=> A = 7623
Finding out compound interest :
- Here we got amount that is Rs.7623 and we already know that principal is Rs.6000.
Putting the values,
C.I. = 7623 - 600
C.I. = 1623