find the compound interest on rupees 1000 10% per annum for 2 years
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compound interest after 2yrs of 1000 Rs at the rate 10% per annum is 210 Rs.
it is given that principal , P = 1000 Rs.
rate of interest , r = 10% per annum
time duration, n = 2 yrs
using formula, C.I = P[(1 + r/100)ⁿ - 1]
= 1000[(1 + 10/100)² - 1]
= 1000[(1 + 1/10)² - 1]
= 1000[(1 + 0.1)² - 1]
= 1000[(1.1)² - 1]
= 1000[1.21 - 1]
= 1000 × 0.21
= 210 Rs.
hence, compound interest = 210 Rs.
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