find the compound interest on rupees 1000 at 10% per annum for 2 years
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Answered by
5
Given
p = 1000
R = 10%
t = 2year
A = p( 1+r/100)^t
A = 1000(1+10/100)^2
A = 1000(1+1/10)^2
A = 1000*121/100
A = 1210
Ci = A - p
so
Ci = 210
Answered by
6
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Refer to the given attachment
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