Question

find the compound interest on rupees 10000 for 1 year at 20% per annum compounded quarterly​

Answer 1

Answer:

put the formula of compound interest

Answer 2

Answer:

Rs 2155.06

Step-by-step explanation:

Principal = Rs 10,000

Rate = 20%

Time = 1 year

It is given that Interest Is compounded Quarterly :

Then,

$\textbf{\underline{\underline{According\:To\:Question :}}}$

Rate = $\frac{20}{4}$ = 5%

Time = 1 × 4 = 4 years

Compound Interest =

$\sf \: Amount = P \: (1 + \dfrac{r}{100} ) ^{n}$

$\sf \: Amount = 10000(1 + \dfrac{5}{100} ) ^{4}$

$\sf \: Amount = 10000(1 + \dfrac{1}{20} ) ^{4}$

$\sf \: Amount = 10000( \dfrac{21}{20} ) ^{4}$

$\sf \: Amount = 10000 \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20} \times \frac{21}{20}$

$\sf \: Amount = \dfrac{21\: \times\: 21\: \times\: 21 \times\: 21}{2\:\times\:2 \times\:2\: \times\:2}$

$\sf \: Amount = \dfrac{194481}{16}$

$\sf \:Amount = 12155.06$

Compound Interest = Amount - Principal

$\implies$ Rs 12155.06 - Rs 10000

$\huge{\boxed{\tt{Rs\:2155.06}}}$