Question

find the compound interest on rupees 10000 for 2 1/2 years at 5% per annum compounded annually​

Answer 1

Answer:

Therefore, Compound Interest would be 12100rs.

Step-by-step explanation:

Compound interest is Rs.2100.

Step-by-step explanation:

Given:-

Principal is Rs.10000.

Rate of interest is 10%.

Time period is 2 years.

To find:-

Compound interest.

Solution:-

We do not have Amount for finding Compound interest. So, First we will find Amount.

Here, Interest is Compounded annually

So,

Where,

P is principal.

r is rate of interest.

n is time period

So, Put the values in formula:

Amount is Rs.12100

Now,

Therefore,

Compound interest is Rs. 2100.

Answer 2

to find the compound interest:-

formula:-

CI=p(1+r/100)÷t

CI=10,000(1+5/100)÷2 1/2

CI=10,000(6/100)÷5/2

CI=10,000×0.06÷5/2

CI=600÷5/2

CI=600×2/5

CI=120×2('120'after divided 600 by 5)

CI=240@ns

ANSWER:-

SO,THE COMPOUND INTEREST IS $240.

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